// LastwordLength.cpp : Defines the entry point for the console application.
//
/*
Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example,
Given s = "Hello World",
return 5. 
*/

#include "stdafx.h"
#include <stdio.h>
#include <string.h>
class Solution {
public:
    int lengthOfLastWord(const char *s) {
        // Start typing your C/C++ solution below
        // DO NOT write int main() function
        if(NULL == s)
            return 0;
        int len = strlen(s);
        if(len == 0) return 0;
        int i = len -1;
		while (i >= 0 && s[i] == ' ')  
            --i;
		if(i<0)
			return 0;
       
		int n=0;
		i = len-1;
        while(i>=0)
        {
            if(s[i] ==' ')
                return n;
            else
            {
                n++;
                i--;
            }
            
        }
        
        return n;
        
    }
};

int _tmain(int argc, _TCHAR* argv[])
{
	Solution S;
	int ret = S.lengthOfLastWord("    day ");
	return 0;
}

